How do you write $7 y = - 5 x - 35$ $7y=-5x-35$ in standard form?

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How do you write $7 y = - 5 x - 35$ $7y=-5x-35$ in standard form?

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Answer 1 · 2015-07-08T06:30:17

The standard form will be $5 x + 7 y + 35 = 0$ $5x + 7y + 35 = 0$

Explanation:

Because the standard form is $x + y +$ $x+y+$ constant $= 0$ $=0$

The standard form will be $5 x + 7 y + 35 = 0$ $5x + 7y + 35 = 0$

Answer 2 · 2015-07-08T06:51:19

Rearrange the equation so it fits the form $A x + B y = C$ $Ax+By=C$ , where $A$ $A$ is not negative, and $A$ $A$ and $B$ $B$ are not both equal to zero.

Explanation:

The standard form of a linear equation is $A x + B y = C$ $Ax+By=C$ , where $A$ $A$ is not negative and $A$ $A$ and $B$ $B$ are not both equal to zero.

$7 y = - 5 x - 35$ $7y=-5x-35$

Add $5 x$ $5x$ to both sides of the equation.

$5 x + 7 y = - 35$ $5x+7y=-35$

The equation is now in standard form.

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How do you write $7 y = - 5 x - 35$ $7y=-5x-35$ in standard form?

2 Answers

Explanation:

Explanation:

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Humanities

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How do you write 7y=−5x−357y=-5x-35 in standard form?

2 Answers

Explanation:

Explanation:

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How do you write $7 y = - 5 x - 35$ $7y=-5x-35$ in standard form?