Question

How do you write `8^(5/3) = 32` in logarithmic form?

Answer 1

`log_8 32=5/3`

Explanation:

By definition
`log_ab=c<=>a^c=b`
here`a =8,c=5/3 and b=32`

`:.8^(5/3)=32=>log_8 32=5/3`