How do you write # -8y= 20+2/5x# in standard form?

1 Answer
Sep 9, 2015

#2x+40y=-100#

Explanation:

"Standard form" for a linear equation is
#color(white)("XXX")Ax+By=C#
#color(white)("XXXXXX")# where #A, B, C in ZZ, A>=0#

#-8y=20+2/5x#

#rarr -40y=100+2x#

#rarr 0 = 100 +2x+40y#

#rarr -100 = 2x+40y#

#rarr 2x+40y = -100color(white)("XXXXXX")#which is in "standard form"