How do you write 98 as a product of prime factors?
1 Answer
Nov 19, 2016
Answer:
Explanation:
Since
#98/2 = 49#
Try each possible prime factor in turn:

#49# ends in an odd digit, so is not divisible by#2# . 
The sum of its digits is
#4+9 = 13# , which is not divisible by#3# , so#49# is not divisible by#3# either. 
#49# does not ends with#5# or#0# , so is not divisible by#5# . 
#49# is divisible by#7# . We find:#49/7 = 7#
So:
#98 = 2*7*7#
We can also draw this as a factor tree: