How do you write $-9b^2+10b-b^6$ in standard form and what is the leading coefficients?

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Answer 1 · 2017-11-21T17:13:04

See a solution process below:

Standard form for a polynomial has the terms descending by the power of the exponent. The standard form of this expression is:

$-b^6 - 9b^2 + 10b$

We can rewrite this as:

$-1b^6 - 9b^2 + 10b$

Therefore, the leading coefficient is: -1

How do you write -9b^2+10b-b^6-9b^2+10b-b^6 in standard form and what is the leading coefficients?