# How do you write (9sqrt8)/(12sqrt16) in simplest radical form?

$\frac{9 \sqrt{8}}{12 \sqrt{16}}$ = $\frac{3 . 3 . \sqrt{2} . \sqrt{4}}{3 . 2. 2 . \sqrt{16}}$ = $\frac{\cancel{3} . 3 . \sqrt{2} . \cancel{2}}{\cancel{3} . \cancel{2} . 2 . 4}$ = $\frac{3 \sqrt{2}}{8}$