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How do you write $9 x - x^{2} = 62 + 4 x - 1$ $9x-x^2=62+4x-1$ in standard form?

1 Answer

Jun 2, 2015

$y = - x^{2} + 9 x - 4 x - 62 + 1 =$ $y = -x^2 + 9x - 4x - 62 + 1 =$ 0

$y = - x^{2} + 5 x - 61$ $y = -x^2 + 5x - 61$ = 0

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