How do you write a Lewis structure for #CH_3NH_3^+#?

1 Answer
Jan 2, 2017

Answer:

Count up the valence electrons............

Explanation:

And that is #6# from the hydrogens, #5# from the nitrogen, and #4# from the carbon, i.e. #15#, from which subtract #1# to account for the positive charge on the ammonium centre. We are left with #14# electrons, or #7# electron pairs, to distibute across the central carbon and nitrogen centres.

#H_3C-N^(+)H_3#. Here, there are #3xxC-H# bonds, #1xxC-N# bond, and #3xxN-H# bonds, i.e. 7 electron pairs AS REQUIRED.

Can you do same for #CH_4# and #NH_4^+#?