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How do you write a polynomial function in standard form with the zeroes x=3,-2,1?

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Jun 7, 2015

$f (x) = (x - 3) (x + 2) (x - 1)$ $f(x) = (x-3)(x+2)(x-1)$

$= (x^{2} - x - 6) (x - 1)$ $=(x^2-x-6)(x-1)$

$= (x^{2} - x - 6) x - (x^{2} - x - 6)$ $=(x^2-x-6)x-(x^2-x-6)$

$= x^{3} - 2 x^{2} - 5 x + 6$ $=x^3-2x^2-5x+6$

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