How do you write a possible quadratic equation in standard form that has the given roots {1+or-i}?

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Answer 1 · 2018-03-29T06:09:08

The possible cubic equation happens to be:

#x^3-x^2+x-1=0#

roots are
#x=1#

#x-1=0#

#x=-i#

#x+i=0#

Complex numbers occur always in conjugates

#x=i#,
#x-i=0#

#x=-i#,
#x+i=0#

Hence, the factors are:

#(x-1), (x-i), (x+i)#

#(x-1)(x-i)(x+i)=0#

#(x-1)(x^2+1)=0#

The possible cubic equation happens to be:

#x^3-x^2+x-1=0#