How do you write a quadratic equation in standard form that has two solutions, 10 and -4 with the leading coefficient must be 1?

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Answer 1 · 2016-10-06T16:59:43

The reqd. qudr. eqn. is #f(x)=x^2-6x-40=0.#

Let #f(x)=0# be the desired qudr. eqn.

It has two solns. #10" & "-4#.

Therefore, #(x-10) and (x-(-4))=(x+4)# are the factors of #f(x)#.

#rArr f(x)=k(x-10)(x+4), k in RR-{0}.#

# rArr" leading co-eff of "#f#" is "k.#

But, given that, #k=1.#

#f(x)=(x-10)(x+4)#

Hence, the reqd. qudr. eqn. is #f(x)=x^2-6x-40=0.#