How do you write a rule for the nth term of the arithmetic sequence and then find #a_22# given #d=14, a_6=-10#?

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Answer 1 · 2017-09-09T11:31:45

# a_n= a_1+(n-1)d , a_22=214#

For arithmatic progression series ,

#n# th term is # a_n= a_1+(n-1)d #, where #a_1.n,d# are

first term , number of terms and common difference respectively.

#a_6=-10 , d=14 , n=6 , a_1= ? :. -10 = a_1+(6-1)*14 #

or # a_1= -10-70= -80 ; a_22=? #

# a_22= a_1+(n-1)d or a_22= -80 +(22-1)*14 # or

#a_22= -80 +294 =214# [Ans]