How do you write a rule for the nth term of the geometric term and then find #a_6# given #r=3, a_1=2#?

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Answer 1 · 2017-10-30T01:38:53

From the reference Geometric Progression we use the general form:

#a_n = a_1r^(n-1)#

Substitute #a_1 = 2# and #r = 3# into the general form:

#a_n = 2(3)^(n-1)#

Substitute #n=6#

#a_6 = 2(3)^(6-1)#

#a_6 = 2(3)^5#

#a_6 = 486#