How do you write an equation in point-slope form for the given (6, 1), (-4. 1)?

1 Answer
Aug 23, 2015

#y-1 = 0*(x-6)color(white)("XXXX")#in explicit point slope form
or#color(white)("XXXXX")y=1# in more common form.

Explanation:

Given #(6,1)# and #(-4,1)#
the change in #y# is zero
and
since the slope is defined as
#color(white)("XXX")m = ("change in y")/("change in x")#
The slope is
#color(white)("XXX")m = 0#

For a line with slope #m# through a point #(hatx,haty)#
the slope-point form is
#color(white)("XXX")(y-haty) = m(x-hatx)#

We have a slope of #m=0# and can use #(hatx,haty) = (6,1)#
to obtain the explicit slope-point form shown in the answer.