How do you write an equation in point-slope form for the line passing through the points (2,8) and (3,4)?

1 Answer
Apr 2, 2015

The Point-Slope form of the Equation of a Straight Line is:

# (y-k)=m*(x-h) #
#m# is the Slope of the Line
#(h,k)# are the co-ordinates of any point on that Line.

  • To find the Equation of the Line in Point-Slope form, we first need to Determine it's Slope . Finding the Slope is easy if we are given the coordinates of two points.

Slope(#m#) = #(y_2-y_1)/(x_2-x_1)# where #(x_1,y_1)# and #(x_2,y_2)# are the coordinates of any two points on the Line

The coordinates given are #(3,4)# and #(2,8)#

Slope(#m#) = #(8-4)/(2-3)# = #4/-1# = #-4#

  • Once the Slope is determined, pick any point on that line. Say #(2,8)#, and Substitute it's co-ordinates in #(h,k)# of the Point-Slope Form.

We get the Point-Slope form of the equation of this line as:
#(y-8)=(-4)*(x-2)#

  • Once we arrive at the Point-Slope form of the Equation, it would be a good idea to Verify our answer. We take the other point #(3,4)#, and substitute it in our answer.

#(y-8) = 4-8 = -4#

#(-4)*(3-2) = (-4)*1 = -4#

As the left hand side of the equation is equal to the right hand side, we can be sure that the point #(3,4)# does lie on the line.

  • The graph of the equation would look like this:

graph{-4x+16 [-18.51, 18.55, -9.27, 9.26]}