Question

How do you write an equation in standard form for a line which passes through (1, 3) and (4, 4)?

Answer 1

Start off by looking at your formula for a straight line, which is: `Y = mX + c` ... you have got two points, so we can find the gradient of the line that passes through the two points `m` where we have got the formula `m = (Y2 - Y1)/(X2 - X1)`

so we have `m= (4-3)/(4-1) = 1/3`

then we will put that into our formula, so we get

`Y = (1/3)X + c`

now you place either one of the points in, I will choose `(1,3)`
so we get.

`3 = (1/3)(1) + c`
`c = 3 - 1/3`
`c = 8/3`

now that we have solved for `c` we simply put it into our formula for a straight line. which gets us to.

`Y = (1/3)X + (8/3)`
where `m = (1/3)` and `c = (8/3)` graph{(1/3)x + 8/3 [-2.896, 7.1, -0.3, 4.7]}