How do you write an equation in standard form for a line which passes through (2,-6) and (-9,6)?
1 Answer
May 20, 2015
Line equation in standard form: y = ax + b
Find a and b by writing that this line passes at point (2, -6) and point (-9, 6)
-6 = 2a + b -> b = -2a - 6
6 = -9a + b -> 6 = -9a - 2a - 6 -> -11a = 12 -->
b = -2a - 6 = 22/12 - 72/12 = -50/12 = -25/6 ->
