How do you write an equation in standard form for a line which passes through points (-1,-1) and (1,3)?

1 Answer
Jul 2, 2018

#2x-y=-1#

Explanation:

#"the equation of a line in "color(blue)"standard form"# is.

#color(red)(bar(ul(|color(white)(2/2)color(black)(Ax+By=C)color(white)(2/2)|)))#

#"where A is a positive integer and B, C are integers"#

#"obtain the equation in "color(blue)"slope-intercept form"#

#•color(white)(x)y=mx+b#

#"where m is the slope and b the y-intercept"#

#"to calculate m use the "color(blue)"gradient formula"#

#•color(white)(x)m=(y_2-y_1)/(x_2-x_1)#

#"let "(x_1,y_1)=(-1,-1)" and "(x_2,y_2)=(1,3)#

#m=(3-(-1))/(1-(-1))=4/2=2#

#y=2x+blarrcolor(blue)"is the partial equation"#

#"to find b substitute either of the 2 given points into"#
#"the partial equation"#

#"using "(1,3)" then"#

#3=2+brArrb=3-2=1#

#y=2x+1larrcolor(red)"in slope-intercept form"#

#"rearranging gives"#

#2x-y=-1larrcolor(red)"in standard form"#