How do you write an equation in standard form given point (-2,-3) and (3,2)?

1 Answer
Apr 18, 2017

"the equation of line is "-x+y=-1the equation of line is x+y=1

Explanation:

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"let P(x,y) be a Point on the line passed A(-2,-3) and B(3,2)."let P(x,y) be a Point on the line passed A(-2,-3) and B(3,2).

"Since "alpha=beta ," we can write as "tan alpha=tan betasince α=β, we can write as tanα=tanβ

tan alpha=(y+3)/(x+2)tanα=y+3x+2

tan beta=(2-y)/(3-x)tanβ=2y3x

(y+3)/(x+2)=(2-y)/(3-x)y+3x+2=2y3x

(y+3)(3-x)=(x+2)(2-y)(y+3)(3x)=(x+2)(2y)

3y-xy+9-3x=2x-xy+4-2y3yxy+93x=2xxy+42y

3y+2y-cancel(x y)+cancel(x y)-3x-2x=+4-9

cancel(5)y-cancel(5)x=-cancel(5)

y-x=-1

-x+y=-1