How do you write an equation of a circle whose diameter has endpoints (-4, 2) and (4, -4)?

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Answer 1 · 2018-03-11T19:14:51

#x^2 +y^2+2y=24#

This is the equation of the circle.

The equation of a circle with given end points of Diameter as #(x_1,y_1),(x_2,y_2)# is #(x-x_1)(x-x_2)+(y-y_1)(y-y_2)=0#

Using this formula we get the equation as :-

#(x-(-4))(x-4)+(y-2)(y-(-4))=0#

#rArr(x+4)(x-4)+(y-2)(y+4)=0#

#rArrx^2 +y^2+2y-24=0#

#:.x^2 +y^2+2y=24#