How do you write an equation of a line in slope intercept form if the line has a slope of -2/3 and contains the point (2,-2)?

Apr 16, 2018

$2 x + 3 y + 2 = 0$

Explanation:

$S l o p e = m = - \frac{2}{3} , \left({x}_{1} , {y}_{1}\right) = \left(2 , - 2\right)$

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$\text{Point - Slope Form } \left(y - {y}_{1}\right) = m \cdot \left(x - {x}_{1}\right)$

$y + 2 = - \left(\frac{2}{3}\right) \cdot \left(x - 2\right)$

$3 y + 6 = - 2 x + 4$

$2 x + 3 y + 2 = 0$