How do you write an equation of a line passing through (4, -3), perpendicular to #y=-4x+3#?
1 Answer
Mar 17, 2018
Explanation:
#"the equation of a line in "color(blue)"slope-intercept form"# is.
#•color(white)(x)y=mx+b#
#"where m is the slope and b the y-intercept"#
#y=-4x+3" is in this form"#
#"with slope m "=-4#
#"Given a line with slope m then the slope of a line"#
#"perpendicular to it is "#
#•color(white)(x)m_(color(red)"perpendicular")=-1/m#
#rArrm_("perpendicular")=-1/(-4)=1/4#
#rArry=1/4x+blarrcolor(blue)"is the partial equation"#
#"to find b substitute "(4,-3)" into the partial equation"#
#-3=1+brArrb=-3-1=-4#
#rArry=1/4x-4larrcolor(red)"perpendicular line"#