How do you write an equation of a line with point (5/4, 1), (-1/4, 3/4)?
1 Answer
Jun 9, 2017
#y=1/6+19/24#
Explanation:
Given -
#(x_1,y_1)=(5/4,1)#
#(x_2,y_2)=(-1/4,3/4)#
#y-y_1=(y_2-y_1)/(x_2-x_1)(x-x_1)#
#y-1=((3/4)-1)/((-1/4)-5/4)(x-5/4)#
#y-1=((3-4)/4)/((-1-5)/4)(x-5/4)#
#y-1=((-1)/4)/((-6)/4)(x-5/4)#
#y-1=((1)/4)/((6)/4)(x-5/4)#
#y-1=1/cancel4xxcancel4/6(x-5/4)#
#y-1=1/6(x-5/4)#
#y-1=1/6x-5/24#
#y=1/6x-5/24+1#
#y=1/6x+((-5+24)/24)#
#y=1/6x+((19)/24)#
#y=1/6+19/24#
