How do you write #cosxcscxcotx# in terms of #sinx# and #cosx#?

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Answer 1 · 2017-05-06T12:04:03

#cosx(1/sinx)(cosx/sinx)#

You need to use...

Reciprocal Identity

#cscx = 1/sinx#

and

Quotient Identity

#cotx = cosx/sinx#

After recognizing these identities it is easy to write this in terms of #sinx# and #cosx#

#cosx(1/sinx)(cosx/sinx)#