How do you write e^(1/2)=1.6487 in logarithmic form?

${e}^{\frac{1}{2}} = 1.6487 \iff \ln 1.6487 = \frac{1}{2} , \mathmr{and} , 0.5 .$
Recall that, ${e}^{x} = y \iff \ln y = x .$
$\therefore {e}^{\frac{1}{2}} = 1.6487 \iff \ln 1.6487 = \frac{1}{2} , \mathmr{and} , 0.5 .$