How do you write equation of a line goes through the point (4,-14) (2,-5)?

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Answer 1 · 2018-01-09T12:03:57

#2y+9x-8=0#

Find the gradient

#m= "change in y"/ "change in x"#

#m = (-5 - (-14))/(2-4) = -9/2#

Use the equation:

#y-y_1 = m(x-x_1)#

Substitute the values from any coordinate, #(4,-14)# or #(2,-5)#

#y-(-5)=-9/2(x-2)#

#y+5=-9/2(x-2)#

Get rid of the fraction by multiplying both sides by #2# and expand the brackets:

#2y+10=-9x+18#

And you get the equation:

#2y+9x-8=0#