How do you write Lewis formulas for the reactant and product species in the following chemical equation, including nonbonding electrons? #N(g) + NO(g) -> N NO(g)#

Many free radicals combine to form molecules that do not contain any unpaired electrons. The driving force for the radical-radical combination reaction is the formation of a new electron-pair bond.

1 Answer
Aug 2, 2017

Answer:

We gots formal separation of charge for #"nitrous oxide"#.....

Explanation:

#N-=stackrel(+)N-O^(+)#; going form the nitrogen around the left there are 5, 4, and 7 valence electrons, giving 7, 6, and 8 electrons associated with each atom, and formal electronic charges of #stackrel(0)N#, #stackrel(+I)N#, and #stackrel(-I)O#

For nitrogen monoxide we have a radical species, with 11 electrons to distribute......#*stackrel(..)N=stackrel(ddot)O:# is the usual representation. Clearly, the would react with atomic nitrogen gas.....

#N(g) + N=O(g)rarrN_2O(g)#

Can you do #NO_2# and #N_2O_4#? The former is a radical species, and both Lewis structures display charge separation.