How do you write ${log}_{.25} 16 = - 4$ $log_.25 16=-4$ in exponential form?

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Answer 1 · 2018-07-10T12:33:26

${(0.25)}^{- 4} = 16$ $(0.25)^-4=16$

${log}_{a} m = x$ $log_a m= x$ then , $a^{x} = m$ $a^x =m$

${log}_{.25} 16 = - 4 or {log}_{\frac{1}{4}} 16 = - 4$ $log_.25 16 = -4 or log_(1/4) 16 = -4$ or

$16= (1/4)^-4 or 16 = 1/(1/4)^4 :. 16 = 16$

$(0.25)^-4=16$ [Ans]

How do you write log_.25 16=-4log.2516=−4log_.25 16=-4 in exponential form?