How do you write #log_3 27=x# in exponential form?
2 Answers
Aug 3, 2016
Explanation:
Using the
#color(blue)"law of logarithms"#
#color(orange)"Reminder" color(red)(|bar(ul(color(white)(a/a)color(black)(log_b a=nhArra=b^n)color(white)(a/a)|)))# here a = 27 , b = 3 and n = x
#rArr27=3^x" in exponential form"# By the way,
#x=3" since" 27=3^3#
Aug 3, 2016
Explanation:
When we write
In your problem, we want to find
Since