# How do you write #log_3 27=x# in exponential form?

##### 2 Answers

Aug 3, 2016

#### Explanation:

Using the

#color(blue)"law of logarithms"#

#color(orange)"Reminder" color(red)(|bar(ul(color(white)(a/a)color(black)(log_b a=nhArra=b^n)color(white)(a/a)|)))# here a = 27 , b = 3 and n = x

#rArr27=3^x" in exponential form"# By the way,

#x=3" since" 27=3^3#

Aug 3, 2016

#### Explanation:

When we write

In your problem, we want to find

Since