How do you write #log_626 5=1/4# in exponential form?

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Answer 1 · 2016-07-10T03:56:27

#625^(1/4)=5#

To start out, I believe your question had a typo in it. It should be 625 instead of 626.

To turn a logarithm into an exponent, you can follow the basic form: #log_a b = c => a^c = b#.

If you would like to simplify it further, you can say #root(4)625 = 5#.

Answer 2 · 2016-07-10T03:59:49

#5=625^(1/4)#

Use, if log_b a = c#. then# a = b^c#. This is called inverion..

Here, #a = 5, b = 625 and c = 1/4#.

So, the answer is #625^(1/4)#.