# How do you write out the formula, complete ionic, and net ionic reaction for a reaction occurring when lead(IV) nitrate reacts with barium chromate?

Sep 22, 2016

$2 B a C r {O}_{4} \left(a q\right) + P b {\left(N {O}_{3}\right)}_{4} \left(a q\right) \rightarrow P b {\left(C r {O}_{4}\right)}_{2} \left(s\right) \downarrow + 2 B a {\left(N {O}_{3}\right)}_{2} \left(a q\right)$

#### Explanation:

I have an idea that barium chromate is pretty insoluble stuff. Nevertheless, lead(IV)chromate is probably even more insoluble.

The net ionic equation is:

$P {b}^{4 +} + 2 C r {O}_{4}^{2 -} \rightarrow P b {\left(C r {O}_{4}\right)}_{2} \left(s\right) \downarrow$

The nitrate and the barium ions are along for the ride. I leave it to you to write the formula equation.