Question

How do you write polar coordinates of `(3, -3)`?

Answer 1

The coordinate (3,-3) is in Quadrant IV ....

Explanation:

`r=sqrt(x^2+y^2)=sqrt(3^2+(-3)^2)=3sqrt2`

Now, the reference angle in Quadrant IV is ...

reference angle `=tan^1(3/3)=45^0`

`theta=270^o + 45^o=315^o`

polar coordinate `(r,theta)=(3sqrt2, 315^o)=(3sqrt2,(7pi)/4)`

hope that helped