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How do you write $sec (2 x)$ $sec(2x)$ in terms of sinx?

1 Answer

Oct 31, 2016

$sec (2 x) = \frac{1}{1 - 2 {sin}^{2} (x)}$ $sec(2x) = 1/(1 - 2sin^2(x))$

Explanation:

$sec (2 x) = \frac{1}{cos (2 x)} = \frac{1}{1 - 2 {sin}^{2} (x)}$ $sec(2x) = 1/cos(2x) = 1/(1 - 2sin^2(x))$

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