# How do you write standard form of quadratic equation of vertex (-1,5) and yint =3?

##### 1 Answer

#### Answer:

#### Explanation:

The vertex form for a quadratic is

for a parabola with vertex at

Since we want a parabola with vertex at

It must have the form:

So what remains is to determine the value of

W are told that

Remembering that the y-intercept is the value of

by replacing

So the complete form for the equation of this parabola is

Here is a graph of

graph{(-2)*(x+1)^2+5 [-6.735, 7.31, -0.513, 6.507]}