# How do you write the complex conjugate of the complex number 2ix - i?

Jan 4, 2017

$t i l \mathrm{de} z = - i \left(2 x - 1\right)$
if $z = a + i b$ then conjugate $t i l \mathrm{de} z = a - i b$
here $z = i \left(2 x - 1\right)$, ie $b = 2 x - 1$
So $t i l \mathrm{de} z = - i \left(2 x - 1\right)$