Question

How do you write the complex conjugate of the complex number `(7A + 3B - 4i)`?

Answer 1

`(7A+3B+4i)`.

Explanation:

The Complex Conjugate of `(x+iy)` is `(x-iy)`, &, vise-versa.

Therefore, the reqd. coj. of `(7A+3B-4i)` is `(7A+3B+4i)`.