How do you write the complex conjugate of the complex number #8 + 4i#?

1 Answer
Jul 1, 2016

Answer:

#|8+4i| = 4sqrt(5)#

Explanation:

Given a complex number #a+bi#, the complex conjugate of that number, denoted #|a+bi|#, is given by

#|a+bi| = sqrt(a^2+b^2)#

and represents the distance of that number from the origin on the complex plane.

In our case, then we have the complex conjugate of #8+4i# as

#|8+4i| = sqrt(8^2+4^2) = sqrt(64+16) = sqrt(80) = 4sqrt(5)#