# How do you write the complex number in standard form #3/2(cos300+isin300)#?

##### 1 Answer

Aug 15, 2017

#### Answer:

#### Explanation:

I'll assume the trigonometric arguments are in **degrees**.

We're asked to find the standard form of

#3/2(cos[300^"o"] + isin[300^"o"])#

Well,

And

So we have

#3/2(1/2 - (isqrt3)/2) = color(blue)(ulbar(|stackrel(" ")(" "3/4 - (3sqrt3)/4i" ")|)#