How do you write the complex number #z = −2 − 2isqrt3 # in trigonometric form?

1 Answer
Feb 18, 2016

Answer:

As you can see this is the #30^0, 60^0, 90^0# right angle triangle which happen to have #2, sqrt(3), 1# relationship between the sides.
The phasor that you were given is scale by 2. See image...
From this the magnitude of you Phasor, P:#|P| = 4#
and the direction angle is #alpha = 240^0# see image
Thus you can write:
#P = 4cos240 + i4sin240 = -2 - i3.46 = -2 -i2sqrt(2) #
enter image source here

Explanation:

See above it is self evident on the image...