How do you write the complex number #z = 8 − 8i# in trigonometric form? Precalculus Complex Numbers in Trigonometric Form Trigonometric Form of Complex Numbers 1 Answer Eddie Jul 23, 2016 #= 8 sqrt 2 e^(-i pi / 4 ) # Explanation: #8 - 8i# #= 8(1 - i)# #= 8 sqrt 2( 1/sqrt 2 - i/sqrt 2)# #= 8 sqrt 2 e^(-i pi / 4 ) # Answer link Related questions How do I find the trigonometric form of the complex number #-1-isqrt3#? How do I find the trigonometric form of the complex number #3i#? How do I find the trigonometric form of the complex number #3-3sqrt3 i#? How do I find the trigonometric form of the complex number #sqrt3 -i#? How do I find the trigonometric form of the complex number #3-4i#? How do I convert the polar coordinates #3(cos 210^circ +i\ sin 210^circ)# into rectangular form? What is the modulus of the complex number #z=3+3i#? What is DeMoivre's theorem? How do you find a trigonometric form of a complex number? Why do you need to find the trigonometric form of a complex number? See all questions in Trigonometric Form of Complex Numbers Impact of this question 2422 views around the world You can reuse this answer Creative Commons License