# How do you write the equation (1/3)^-2=9 in logarithmic form?

$- 2 \log \left(\frac{1}{3}\right) = \log 9$
Left Hand Side: $\log {\left(\frac{1}{3}\right)}^{-} 2 = - 2 \log \left(\frac{1}{3}\right) = 2 \log 3$
Right Hand Side: $\log \left(9\right) = \log \left({3}^{2}\right) = 2 \log 3$