# How do you write the equation #4x^2+4y^2-24y+36=0# in standard form and find the center and radius?

##### 1 Answer

Given

The a conic section of the general form:

Matching coefficients between equations [1] and [2] we observe that:

A = B = 4#

This identifies the given conic section as a circle of the general form:

Begin progress to the form of equation [3] by dividing equation [1] by 4:

Subtract 9 from both sides:

Because there is no x term, we conclude that

There is a y term, therefore, we add k^2 to both sides of equation [1.2]:

From the pattern

Simplify:

Because the right side of equation [1.4] this indicates that the radius is 0:

This degenerates into the point