How do you write the equation #6^-2=1/36# into logarithmic form?
1 Answer
Apr 29, 2018
Explanation:
#"using the "color(blue)"law of logarithms"#
#•color(white)(x)log_b x=nhArrx=b^n#
#"here "b=6,n=-2" and "x=1/36#
#rArrlog_6(1/36)=-2hArr6^-2=1/36#
