How do you write the equation 7^-2=1/49 in logarithmic form?

May 10, 2018

${\log}_{7} \left(\frac{1}{49}\right) = - 2$

Explanation:

If ${b}^{x} = y$, then ${\log}_{b} y = x$
Therefore, since ${7}^{-} 2 = \frac{1}{49}$, then ${\log}_{7} \left(\frac{1}{49}\right) = - 2$