Question

How do you write the equation in point slope form given point (6,1) and perpendicular to y=-x+6?

Answer 1

`y-1=x-6`

Explanation:

`"the equation of a line in "color(blue)"slope-intercept form"` is.

`•color(white)(x)y=mx+b`

`"where m is the slope and b the y-intercept"`

`y=-x+6" is in this form"`

`"with slope m "=-1`

`"given a line with slope m then the slope of a line"`
`"perpendicular to it is"`

`•color(white)(x)m_(color(red)"perpendicular")=-1/m`

`rArrm_("perpendicular")=-1/(-1)=1`

`"the equation of a line in "color(blue)"point-slope form"` is.

`•color(white)(x)y-y_1=m(x-x_1)`

`"where m is the slope and "(x_1,y_1)" a point on the line"`

`"here "m=1" and "(x_1,y_1)=(6,1)`

`rArry-1=1(x-6)larrcolor(red)"in point-slope form"`