How do you write the equation in point slope form given point (6,1) and perpendicular to y=-x+6?

1 Answer
May 13, 2018

Answer:

#y-1=x-6#

Explanation:

#"the equation of a line in "color(blue)"slope-intercept form"# is.

#•color(white)(x)y=mx+b#

#"where m is the slope and b the y-intercept"#

#y=-x+6" is in this form"#

#"with slope m "=-1#

#"given a line with slope m then the slope of a line"#
#"perpendicular to it is"#

#•color(white)(x)m_(color(red)"perpendicular")=-1/m#

#rArrm_("perpendicular")=-1/(-1)=1#

#"the equation of a line in "color(blue)"point-slope form"# is.

#•color(white)(x)y-y_1=m(x-x_1)#

#"where m is the slope and "(x_1,y_1)" a point on the line"#

#"here "m=1" and "(x_1,y_1)=(6,1)#

#rArry-1=1(x-6)larrcolor(red)"in point-slope form"#