# How do you write the equation in standard form of a circle with a radius = 4; and center = (-2, 3)?

Nov 30, 2015

The equation is: ${\left(x + 2\right)}^{2} + {\left(y - 3\right)}^{2} = 16$

#### Explanation:

The equation of a circle is ${\left(x - a\right)}^{2} + {\left(y - b\right)}^{2} = {r}^{2}$ where $\left(a , b\right)$ are the coordinates of the centreand $r$ is a radius. So the equation is:

${\left(x - \left(- 2\right)\right)}^{2} + {\left(y - 3\right)}^{2} = {4}^{2}$

Finally:

${\left(x + 2\right)}^{2} + {\left(y - 3\right)}^{2} = 16$