Question

How do you write the equation in standard form of a circle with a radius = 4; and center = (-2, 3)?

Answer 1

The equation is: `(x+2)^2+(y-3)^2=16`

Explanation:

The equation of a circle is `(x-a)^2+(y-b)^2=r^2` where `(a,b)` are the coordinates of the centreand `r` is a radius. So the equation is:

`(x-(-2))^2+(y-3)^2=4^2`

Finally:

`(x+2)^2+(y-3)^2=16`