How do you write the equation of a circle for center:(5,-13) radius:11?

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Answer 1 · 2018-04-27T15:53:20

#color(blue)((x-5)^2+(y+13)^2=121)#

#(x-h)^2+(y-k)^2=r^2#

Where #bbh# and #bbk# are the #bbx# and #bby# coordinates of the centre respectively and #bbr# is the radius.

So:

#h=5#

#k=-13#

#r^2=(11)^2=121#

Plugging these values into equation:

#(x-5)^2+(y-(-13))^2=121#

#(x-5)^2+(y+13)^2=121#