How do you write the equation of the circle centered at ( − 6 , − 10 ) with radius 5/6 ?

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Answer 1 · 2018-05-01T15:10:02

#(x+6)^2+(y+10)^2=25/36#

To answer this question, one must know the standard equation of a circle on a coordinate plane:

#(x-h)^2+(y-k)^2=r^2#

in which the center of the circle is (#h#, #k#) with radius #r#.

Note that the center and radius of our circle are given to us in the problem, the center being at point (-6, -10) and the radius being 5/6!

Therefore, we have assigned our values:

#h# = -6, #k# = -10, #r# = 5/6

Now plug these values into the standard equation mentioned above:
#(x-(-6))^2+(y-(-10))^2=(5/6)^2#
= #(x+6)^2+(y+10)^2=25/36#

The simplified equation above is your final answer!