How do you write the equation of the circle centered at ( − 6 , − 10 ) with radius 5/6 ?

1 Answer
May 1, 2018

(x+6)^2+(y+10)^2=25/36

Explanation:

To answer this question, one must know the standard equation of a circle on a coordinate plane:

(x-h)^2+(y-k)^2=r^2

in which the center of the circle is (h, k) with radius r.

Note that the center and radius of our circle are given to us in the problem, the center being at point (-6, -10) and the radius being 5/6!

Therefore, we have assigned our values:

h = -6, k = -10, r = 5/6

Now plug these values into the standard equation mentioned above:
(x-(-6))^2+(y-(-10))^2=(5/6)^2
= (x+6)^2+(y+10)^2=25/36

The simplified equation above is your final answer!