# How do you write the equation x^2-4x+y^2+10y=-25 in standard form and find the center and radius?

Apr 2, 2018

${\left(x - 2\right)}^{2} + {\left(y + 5\right)}^{2} = 4$
centre (2,-5)

#### Explanation:

Completing the square
${x}^{2} - 4 x + 4 + {y}^{2} + 10 y + 25 = - 25 + 25 + 4$
Remember, whatever you do on one side you also do on the other side
${\left(x - 2\right)}^{2} + {\left(y + 5\right)}^{2} = 4$
which is in the general form: ${\left(x - h\right)}^{2} + {\left(y - k\right)}^{2} = {r}^{2}$