How do you write the equation #y = —1/4x + 3# in standard form?

1 Answer
Madi
Oct 31, 2015

#x+4y=12#

Explanation:

#y=-1/4x+3#

First, get rid of the fraction by multiplying everything by the denominator, which in this case, is #4#.

#(4)(y) = -1/4x(4) + 3(4)#

#4y=-x+12#

Since the standard form is #Ax+By=C#, move #x# to the same side of the equal sign as the #y#.

And you get #4y+x=12#

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